Post by speedway_history on May 29, 2012 15:56:07 GMT 1
24.05.12
Swindon versus Peterborough
Swindon..56
1..H Andersen..2',2',2,3,2' = 11+3
2..N Morris..3,3,2',1' = 9+2
3..T Batchelor..2,2,2,2' = 8+1
4..T Kurtz (G)..0,0,1' = 1+1
5..S Stead..3,1',2,1 = 7+1
6..R Aspegren..0,2,1',1 = 4+1
7..P Kildemand..3,1,3,3,3,3 = 16
Peterborough..37
1..K Bjerre..1,3,3,2,0 = 9
2..R Bach..0,1,1,0 = 2
3..M J Jensen..R/R
4..L Sundstrom..3,3,3,2,1 = 12
5..R Fisher (G)..2,1,6,0 = 9
6..R Lawson..2,0,0,0,0 = 2
7..J B Monberg..1',0,0,1,0,1,0 = 3+1
Ht 1..Morris, Andersen, Bjerre, Bach 5-1 (5-1)
Ht 2..Kildemand, Lawson, Monberg, Aspegren 3-3 (8-4)
Ht 3..Sundstrom, Batchelor, Bach, Kurtz 2-4 (10-8)
Ht 4..Stead, Fisher, Kildemand, Monberg 4-2 (14-10)
Ht 5..Bjerre, Batchelor, Bach, Kurtz 2-4 (16-14)
Ht 6..Morris, Andersen, Fisher, Lawson 5-1 (21-15)
Ht 7..Sundstrom, Aspegren, Stead, Monberg 3-3 (24-18)
Ht 8..Kildemand, Morris, Monberg, Bach 5-1 (29-19)
Ht 9..Fisher [T/R], Batchelor, Kurtz, Lawson 3-6 (32-25)
Ht 10..Sundstrom, Andersen, Morris, Monberg 3-3 (35-28)
Ht 11..Bjerre, Stead, Aspegren, Lawson 3-3 (38-31)
Ht 12..Kildemand, Batchelor, Monberg, Lawson 5-1 (43-32)
Ht 13..Andersen, Bjerre, Stead, Fisher 4-2 (47-34)
Ht 14..Kildemand, Sundstrom, Aspegren, Monberg 4-2 (51-36)
Ht 15..Kildemand, Andersen, Sundstrom, Bjerre 5-1 (56-37)
Notes:
1..Ht 3 and Bach takes the R/R for Peterborough.
2..Ht 7 and Monberg takes the R/R for Peterborough.
3..Ht 9 and Fisher takes a tactical ride for Peterborough - his points will count double if he beats an opponent.
4..Ht 10 and Monberg takes the R/R for Peterborough.
5..Ht 11 and Lawson replaces Bach for Peterborough.
6..Ht 12 and Monberg takes the R/R for Peterborough.
7..Ht 14 and Kildemand replaces Kurtz for Swindon.
8..Ht 15 and it's Andersen-Kildemand for Swindon and it's Bjerre-Sundstrom for Peterborough.
Swindon versus Peterborough
Swindon..56
1..H Andersen..2',2',2,3,2' = 11+3
2..N Morris..3,3,2',1' = 9+2
3..T Batchelor..2,2,2,2' = 8+1
4..T Kurtz (G)..0,0,1' = 1+1
5..S Stead..3,1',2,1 = 7+1
6..R Aspegren..0,2,1',1 = 4+1
7..P Kildemand..3,1,3,3,3,3 = 16
Peterborough..37
1..K Bjerre..1,3,3,2,0 = 9
2..R Bach..0,1,1,0 = 2
3..M J Jensen..R/R
4..L Sundstrom..3,3,3,2,1 = 12
5..R Fisher (G)..2,1,6,0 = 9
6..R Lawson..2,0,0,0,0 = 2
7..J B Monberg..1',0,0,1,0,1,0 = 3+1
Ht 1..Morris, Andersen, Bjerre, Bach 5-1 (5-1)
Ht 2..Kildemand, Lawson, Monberg, Aspegren 3-3 (8-4)
Ht 3..Sundstrom, Batchelor, Bach, Kurtz 2-4 (10-8)
Ht 4..Stead, Fisher, Kildemand, Monberg 4-2 (14-10)
Ht 5..Bjerre, Batchelor, Bach, Kurtz 2-4 (16-14)
Ht 6..Morris, Andersen, Fisher, Lawson 5-1 (21-15)
Ht 7..Sundstrom, Aspegren, Stead, Monberg 3-3 (24-18)
Ht 8..Kildemand, Morris, Monberg, Bach 5-1 (29-19)
Ht 9..Fisher [T/R], Batchelor, Kurtz, Lawson 3-6 (32-25)
Ht 10..Sundstrom, Andersen, Morris, Monberg 3-3 (35-28)
Ht 11..Bjerre, Stead, Aspegren, Lawson 3-3 (38-31)
Ht 12..Kildemand, Batchelor, Monberg, Lawson 5-1 (43-32)
Ht 13..Andersen, Bjerre, Stead, Fisher 4-2 (47-34)
Ht 14..Kildemand, Sundstrom, Aspegren, Monberg 4-2 (51-36)
Ht 15..Kildemand, Andersen, Sundstrom, Bjerre 5-1 (56-37)
Notes:
1..Ht 3 and Bach takes the R/R for Peterborough.
2..Ht 7 and Monberg takes the R/R for Peterborough.
3..Ht 9 and Fisher takes a tactical ride for Peterborough - his points will count double if he beats an opponent.
4..Ht 10 and Monberg takes the R/R for Peterborough.
5..Ht 11 and Lawson replaces Bach for Peterborough.
6..Ht 12 and Monberg takes the R/R for Peterborough.
7..Ht 14 and Kildemand replaces Kurtz for Swindon.
8..Ht 15 and it's Andersen-Kildemand for Swindon and it's Bjerre-Sundstrom for Peterborough.